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15y^2+17y+2=0
a = 15; b = 17; c = +2;
Δ = b2-4ac
Δ = 172-4·15·2
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-13}{2*15}=\frac{-30}{30} =-1 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+13}{2*15}=\frac{-4}{30} =-2/15 $
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